A particle move along the parabolic path, x = y^2 + 2y + 2 in such a way that the y-component of velocity vector remain 5 m/s during the motion. The magnitude of the acceleration of the particle is

A particle move along the parabolic path, x = y^2 + 2y + 2 in such a w

1.	A particle move along the parabolic path, x = y^2 + 2y + 2 in such a way that the y-component of velocity vector remain 5 m/s during the motion. The magnitude of the acceleration of the particle is
Answer» A particle move along the parabolic path, x = y^2 + 2y + 2 in such a way that the y-component of velocity vector remain 5 m/s during the motion. The magnitude of the acceleration of the particle is

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A particle move along the parabolic path, x = y^2 + 2y + 2 in such a way that the y-component of velocity vector remain 5 m/s during the motion. The magnitude of the acceleration of the particle is

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