1.

A particle located at x = 0 at time t=0 starts moving along positive x-direction with velocity v that varies as v = asqrt(x). The displacement of the particle varies with time as :

Answer»

`t^(2)`
t
`t^(1//2)`
`t^(3)`

SOLUTION :Here `v=ax^(1//2)`
`(dx)/(DT)=ax^(1//2)`
or `x^(-1//2)dx=a dt`
Intergrating, we GET
`(x^(1//2))/(1//2)`=at `xprop t^(2)`


Discussion

No Comment Found

Related InterviewSolutions