A particle is undergoing SHM. If its potential energy is given by: U = kx^2. What will be the value of x for potential energy to be 1/3rd of kinetic energy? Assume k is force constant.(a) A/√7(b) A/√6(c) A/√3(d) A/√2The question was posed to me in exam.My question is taken from Oscillations in chapter Oscillations of Physics – Class 11

A particle is undergoing SHM. If its potential energy is given by: U =

1.	A particle is undergoing SHM. If its potential energy is given by: U = kx^2. What will be the value of x for potential energy to be 1/3rd of kinetic energy? Assume k is force constant.(a) A/√7(b) A/√6(c) A/√3(d) A/√2The question was posed to me in exam.My question is taken from Oscillations in chapter Oscillations of Physics – Class 11
Answer» The correct option is (a) A/√7 Explanation: Let X = Asin(wt). U = kA^2sin^2(wt)K = 1/2mA^2w^2cos^2(wt).Given: U = 1/3K.kA^2sin^2(wt) = (1/3)*(1/2)mA^2w^2cos^2(wt), and k = mw^2. ∴ TAN^2(wt) = 1/6. Or tan(wt) = 1/√6. ∴ SIN(wt) = 1/√7.x = Asin(wt) = A/√7.

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