A particle is thrown at angle θ to cover maximum range with kinetic energy ‘K’. What is its energy at the highest point?

A particle is thrown at angle θ to cover maximum range with kinetic e

1.	A particle is thrown at angle θ to cover maximum range with kinetic energy ‘K’. What is its energy at the highest point?
Answer» Kinetic energy K, LET VELOCITY of particle ISV. ⇒v=m2K⇒ 21mv2= KVelocity in horizontal direction=vcos(θ)=m2Kcos(θ)Velocity in vertical direction=vsin(θ)=m2Ksin(θ)At highest point, Vertical velocity is ZERO only CONSTANT horizontal velocity is present.Kinetic energy at highest point =21m(vcos(θ))2=21×m×m2Kcos2(θ)=Kcos2(θ)

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A particle is thrown at angle θ to cover maximum range with kinetic energy ‘K’. What is its energy at the highest point?

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