A particle is revolving in a circular path having radius ‘r′=1 m at a speed of 2 m/s. It is increasing its speed at the rate of 3 m/s2. The magnitude of total acceleration of the particle at that instant is

A particle is revolving in a circular path having radius ‘r′=1 m a

1.	A particle is revolving in a circular path having radius ‘r′=1 m at a speed of 2 m/s. It is increasing its speed at the rate of 3 m/s2. The magnitude of total acceleration of the particle at that instant is
Answer» A particle is revolving in a circular path having radius $‘ r^{'} = 1 m$ at a speed of $2 m / s$ . It is increasing its speed at the rate of $3 m / s^{2}$ . The magnitude of total acceleration of the particle at that instant is

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A particle is revolving in a circular path having radius ‘r′=1 m at a speed of 2 m/s. It is increasing its speed at the rate of 3 m/s2. The magnitude of total acceleration of the particle at that instant is

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