A particle is projected with a velocity v (3i-j+2k) m/s and a constant acceleration acting on the particle is a=(-6i+2j-4k then the path of the projectile is- a) straight line b)parabola c) circle d)ellipse

A particle is projected with a velocity v (3i-j+2k) m/s and a constant

1.	A particle is projected with a velocity v (3i-j+2k) m/s and a constant acceleration acting on the particle is a=(-6i+2j-4k then the path of the projectile is- a) straight line b)parabola c) circle d)ellipse
Answer» inly user here is your answer The answer is parabola REASON : When a object is thrown into air with certain velocity and making an angle Φ with HORIZONTAL axis and at ACCELERATION of the BODY is regarded as the projectle » When a body is thrown up then due the gravitational PULL there exits a force downwards and the body falls down If you liked my answer then don't forget to mark as brainliest answer

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A particle is projected with a velocity v (3i-j+2k) m/s and a constant acceleration acting on the particle is a=(-6i+2j-4k then the path of the projectile is- a) straight line b)parabola c) circle d)ellipse​

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A particle is projected with a velocity v (3i-j+2k) m/s and a constant acceleration acting on the particle is a=(-6i+2j-4k then the path of the projectile is- a) straight line b)parabola c) circle d)ellipse