A particle is projected vertically upwards with a of speed 105 m/s. The distance travelled by the particle in the 11th second of its motion is: 9 = 10m/s2 2.5 m 5 m 2 m Zero

A particle is projected vertically upwards with a of speed 105 m/s. Th

1.	A particle is projected vertically upwards with a of speed 105 m/s. The distance travelled by the particle in the 11th second of its motion is: 9 = 10m/s2 2.5 m 5 m 2 m Zero
Answer» e travelled by particle in nth SEC: u = initial VELOCITY = 105 m/sa = acceleration = g = -10m/s²n = 11••• distance travelled in 11TH SECOND of its motion-----------

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A particle is projected vertically upwards with a of speed 105 m/s. The distance travelled by the particle in the 11th second of its motion is: 9 = 10m/s2 2.5 m 5 m 2 m Zero​

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A particle is projected vertically upwards with a of speed 105 m/s. The distance travelled by the particle in the 11th second of its motion is: 9 = 10m/s2 2.5 m 5 m 2 m Zero