A particle is projected vertically from the ground time t1 upto point A ,time t2 from the point A to B and time t3 from B to heighest point and back to the ground .find the height of the middle point of A and B from the ground?

A particle is projected vertically from the ground time t1 upto point

1.	A particle is projected vertically from the ground time t1 upto point A ,time t2 from the point A to B and time t3 from B to heighest point and back to the ground .find the height of the middle point of A and B from the ground?
Answer» Let the height of point B be 'h' and INITIAL velocity of particle be 'u'.Total time of LIGHT =t 1 +t 2 So, time to reach at maximum height = 2t 1 +t 2 APPLYING I equation of motion0=u+(−g)[ 2t 1 +t 2 ]⇒u= 2g(t 1 +t 2 )

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A particle is projected vertically from the ground time t1 upto point A ,time t2 from the point A to B and time t3 from B to heighest point and back to the ground .find the height of the middle point of A and B from the ground?​

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A particle is projected vertically from the ground time t1 upto point A ,time t2 from the point A to B and time t3 from B to heighest point and back to the ground .find the height of the middle point of A and B from the ground?