A particle is projected making angle 45 with horizontal having kinetic energy k. The kinetic energy at highest point will be

A particle is projected making angle 45 with horizontal having kinetic

1.	A particle is projected making angle 45 with horizontal having kinetic energy k. The kinetic energy at highest point will be
Answer» mvv ,and when PARTICLE reach at MAM ht ,its SPEED becomes v'= v/ ROOT2 so new K.E = 1/2 * m * v' * v' = k/2

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A particle is projected making angle 45 with horizontal having kinetic energy k. The kinetic energy at highest point will be

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