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A particle is projected in such a way that it follows a curved path with constant acceleration `vec(a)`. For finite interval of motion. Which of the following option `(s)` may be correct `:` `vec(u)=` initial velocity `vec(a)=` acceleration of particle `vec(v)=` velocity at `tgt0`A. `|vec(a)xxvec(u)|cancel(=)0`B. `|vec(a)xxvec(v)|=0`C. `|vec(u)xxvec(v)|=0`D. `|vec(u).vec(v)|=0` |
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Answer» Correct Answer - A::D If `|vec(a)xxvec(u)|=0` particle its will not forllow curved path. Above described motion is a projectile motion with parabolic path. |
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