A particle is projected from the ground at an angle of 60∘ with the horizontal with speed u=20 m/s. The radius of curvature of the path of the particle, when its velocity makes an angle 30∘ with the horizontal is(g=10 m/s2)

A particle is projected from the ground at an angle of 60∘ with the

1.	A particle is projected from the ground at an angle of 60∘ with the horizontal with speed u=20 m/s. The radius of curvature of the path of the particle, when its velocity makes an angle 30∘ with the horizontal is(g=10 m/s2)
Answer» A particle is projected from the ground at an angle of $60^{\circ}$ with the horizontal with speed $u = 20 m/s$ . The radius of curvature of the path of the particle, when its velocity makes an angle $30^{\circ}$ with the horizontal is $(g = 10 {m/s}^{2})$

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A particle is projected from the ground at an angle of 60∘ with the horizontal with speed u=20 m/s. The radius of curvature of the path of the particle, when its velocity makes an angle 30∘ with the horizontal is(g=10 m/s2)

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