A particle is projected from the ground at an angle of 60∘ with horizontal with speed u=20 m/s. The radius of curvature of the path of the particle, when its velocity makes an angle of 30∘ with horizontal is (Take g=10 m/s2)

A particle is projected from the ground at an angle of 60∘ with hori

1.	A particle is projected from the ground at an angle of 60∘ with horizontal with speed u=20 m/s. The radius of curvature of the path of the particle, when its velocity makes an angle of 30∘ with horizontal is (Take g=10 m/s2)
Answer» A particle is projected from the ground at an angle of $60^{\circ}$ with horizontal with speed $u = 20 m / s$ . The radius of curvature of the path of the particle, when its velocity makes an angle of $30^{\circ}$ with horizontal is (Take $g = 10 m / s^{2}$ )

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A particle is projected from the ground at an angle of 60∘ with horizontal with speed u=20 m/s. The radius of curvature of the path of the particle, when its velocity makes an angle of 30∘ with horizontal is (Take g=10 m/s2)

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