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A particle is projected from the bottom of an inclined plane of inclination `30^@` with velocity of `40 m//s` at an angle of `60^@` with horizontal. Find the speed of the particle when its velocity vector is parallel to the plane. Take `g = 10 m//s^2`. |
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Answer» Correct Answer - C::D Horizontal component of velocity always remains constant `:. 40 cos 60^@ = v cos 30^@` or `v= 40/(sqrt3) m//s`. |
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