A particle is projected from horizontal ground with speed 5ms^(-1) at 53^(@) with horizontal. Find time after which velocity of particle will be 45^(@) with horizontal:

A particle is projected from horizontal ground with speed 5ms^(-1) at

1.	A particle is projected from horizontal ground with speed 5ms^(-1) at 53^(@) with horizontal. Find time after which velocity of particle will be 45^(@) with horizontal:
Answer» `(1)/(10)` SEC `(3)/(10)` sec `(5)/(10)` sec `(7)/(10)` sec Solution : `5cos 53^(@)=v COS 45^(@)` `v SIN 45^(@)=5sin 53^(@)-gt`