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| 1. |
A particle is projected at t = 0 from ground its velocity at t = 8sec is V = (15 i^ + 3 j^)m/s find out (A):- velocity at Max Height (B):- time of flight, range and maximum height |
| Answer» VELOCITY = displacement / time and To find the time of flight, determine the time the projectile takes to reach MAXIMUM height. The time of flight is just double the maximum-height time. At maximum height, vy = 0. The time of flight is also determined SOLELY by the initial velocity in the y direction and the acceleration due to gravity. and for range use An object launched into projectile motion will have an initial LAUNCH angle anywhere from 0 to 90 degrees. The range of an object, given the initial launch angle and initial velocity is found with: R=v2isin2θig R = v i 2 SIN 2 θ i g .the maximum height is given by u²/(2*g) . | |