A particle is projected at an angle of 30∘ w.r.t horizontal with speed 20 m/s. Take the point of projection as the origin of the coordinate axes and find the position vector(in m) of the particle after 1 s. (Take g=10 m/s2)

A particle is projected at an angle of 30∘ w.r.t horizontal with spe

1.	A particle is projected at an angle of 30∘ w.r.t horizontal with speed 20 m/s. Take the point of projection as the origin of the coordinate axes and find the position vector(in m) of the particle after 1 s. (Take g=10 m/s2)
Answer» A particle is projected at an angle of $30^{\circ}$ w.r.t horizontal with speed $20 m / s .$ Take the point of projection as the origin of the coordinate axes and find the position vector(in $m$ ) of the particle after $1 s$ . (Take $g = 10 m / s^{2}$ )

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A particle is projected at an angle of 30∘ w.r.t horizontal with speed 20 m/s. Take the point of projection as the origin of the coordinate axes and find the position vector(in m) of the particle after 1 s. (Take g=10 m/s2)

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