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A particle is performing sinple harmonic motion of period 2 sec. if the greatest speed is `5(m)/(s)` the speed `((m)/(s))` of particle when it is `(3)/(pi)` m from equilibrium is: |
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Answer» Correct Answer - 4 Angular frequency `omega=(2pi)/(2)=pis^(-1)` `vmax=omegaA` `4=piA` `impliesA=(4)/(pi)m` `v=omegasqrt(A^(2)-x^(2))` `=pisqrt((25)/(pi^(2))-(9)/(pi^(2)))=4(m)/(s)`. |
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