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a particle is moving with velocity 5m/stowards east and it's velocity changes to 5m/s north in 10 seconds find the acceleration |
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Answer» acceleration vector=1/2j-1/2iMagnitude of acceleration=√2/2Explanation:CONSIDERING EAST as positive x axis and north as positive y AxisInitial VELOCITY vector(u)=5iFinal velocity vector (V)=5j change in velocity=v-u=5j-5iacceleration = change in velocity/timeacceleration = (5j- 5I)/10acceleration=(5j/10 ) - (5i/10)acceleration=(i/2 )-(j/2)Magnitude=√{(1/2)²+(1/2)²}Magnitude=√2/2 |
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