A particle is moving with angular acceleration of `1.2 rad//s^(2)` on a circle of radius 1m. Finds its total acceleration (in `m//s^(2)`) after rotating `sqrt(6)` rad. If its initial angular velocity is zero.

A particle is moving with angular acceleration of `1.2 rad//s^(2)` on

1.	A particle is moving with angular acceleration of `1.2 rad//s^(2)` on a circle of radius 1m. Finds its total acceleration (in `m//s^(2)`) after rotating `sqrt(6)` rad. If its initial angular velocity is zero.
Answer» Correct Answer - 5 `omega^(2) =2alpha theta` `a_(T)=Rsqrt(4alpha^(2) theta^(2) +alpha^(z))=Rasqrt(4theta^(2)+1)` `=1xx1.2xxsqrt(2.4+1)=6 m//s^(2)`

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A particle is moving with angular acceleration of `1.2 rad//s^(2)` on a circle of radius 1m. Finds its total acceleration (in `m//s^(2)`) after rotating `sqrt(6)` rad. If its initial angular velocity is zero.

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