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A particle is moving such that its position coordinates `(x, y)` are `(2m, 3m)` at time `t=0, (6m, 7m)` at time `t=2 s`, and `(13 m, 14m)` at time `t=5 s`. Average velocity vector`(vec(V)_(av))` from `t=0` to `t=5 s` isA. `(1)/(5) (13 hati +14 hatj)`B. `(7)/(3)(hati +hatj)`C. `2(hati - hatj)`D. `(11)/(5)(hati +hatj)` |
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Answer» Correct Answer - D Average velocity, `v_(av) = ("Net displacement")/("Time taken")` `= ((13 -2)hati+(14-3)hatj)/(5)` `= (11 hati + 11 hatj)/(5) = (11)/(5) (hati +hatj)` |
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