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A particle is moving on a straight line along x -direction.A graph between square of its velocity & position is drawn as shown.Find the magnitude of acceleration (in m/s^(2) ) of particle​

Answer» V 2 =2as+u 2 y=mx+cm=2aa= 2m Slope m ca be calculated asm= x 2 −x 1 y 2 −y 1 = 0.6−0900−3600 =− 0.62700 ∴a=− 2m =− 24500 =−2250km/hr 2 ANSWERED BytopprExplanation:I HOPE THIS IS HELPFUL TO YOU PLZ CHECK MY BIO AND THEN FOLLOW ME ☺️


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