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A particle is moving in a circle of radius r=2 m. Its speed with time varies according to the relation v(t)=4−6t2. What is the magnitude of the total acceleration of the particle at t=2 sec ? Use the value of √769=27.73 for calculation. |
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Answer» A particle is moving in a circle of radius r=2 m. Its speed with time varies according to the relation v(t)=4−6t2. What is the magnitude of the total acceleration of the particle at t=2 sec ? Use the value of √769=27.73 for calculation. |
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