1.

A particle is moving in a circle of radius r=2 m. Its speed with time varies according to the relation v(t)=4−6t2. What is the magnitude of the total acceleration of the particle at t=2 sec ? Use the value of √769=27.73 for calculation.

Answer»

A particle is moving in a circle of radius r=2 m. Its speed with time varies according to the relation v(t)=46t2. What is the magnitude of the total acceleration of the particle at t=2 sec ? Use the value of 769=27.73 for calculation.



Discussion

No Comment Found

Related InterviewSolutions