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a particle is moving along east direction with a velocity v metre per second and suddenly turns along north direction with the same velocity v then it resultant velocity is |
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Answer» Initial velocity =v1=5m/s seast wards. then after TIME t=10 sec towards EAST =5m/s v2=5m/s NORTH wards. towards east =5m/s V RESULTANT =v12+v22 =25+25=52 acceleration a=v=velocity/time =1052=22×22=21towardsn−w |
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