A particle is moving along a straight line y = 3 m at a velocity 5 m/s. Its angular speedabout origin when it is at point P(4 m, 3 m)is

A particle is moving along a straight line y = 3 m at a velocity 5 m

1.	A particle is moving along a straight line y = 3 m at a velocity 5 m/s. Its angular speedabout origin when it is at point P(4 m, 3 m)is
Answer» w = V SIN(Q) / RWHERE r is the position vector of point P(4M, 3M)v sin(Q) is the perpendicular component of velocity to the position vector.OP = r = √(16m2 + 9m2 ) = 5msin(Q) = 3/5-w = (5 x 3/5) / 5 = 0.6 radian / second

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A particle is moving along a straight line y = 3 m at a velocity 5 m/s. Its angular speedabout origin when it is at point P(4 m, 3 m)is​

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A particle is moving along a straight line y = 3 m at a velocity 5 m/s. Its angular speedabout origin when it is at point P(4 m, 3 m)is