Saved Bookmarks
| 1. |
A particle is moving along a straight line. Its displacement-time graph is shown `{:(,,"Column-I",,"Column-II"),(,(A),"Work done on particle from 0 to "t_(1),(P),"Positive"),(,(B),"Work done on particle from " t_(1) " to " t_(2),(Q),"Negative"),(,(C),"Work done on particle from " t_(2) " to " t_(3),(R),"zero"),(,(D),"Work done on particle from " t_(3) " to " t_(4),(S),"Unpredectible"):}`A. `AtoR,BtoR,CtoP,DtoQ`B. `AtoS,BtoR,CtoP,DtoQ`C. `AtoR,BtoS,CtoP,DtoQ`D. `AtoR,BtoR,CtoQ,DtoP` |
|
Answer» Correct Answer - 1 For 0`gttgtt_(0)to`slope=constnt W=0 For `t_(1)lttltt_(2)to`slope=0 W=0 For `t_(2)lttltt_(3)to` slope is increasing W=+ve For `t_(3)lttltt_(4)to` slope is decreasing W=-ve |
|