1.

A particle is moving a straight line with constantacceleration passes through points A and B withvelocity 1 m/s and 4 m/s respectively, find velocity ofthe particle at point p between A and B so that PA/PB=41.√142.√383.√134.√19​

Answer»

ANSWER:

√13 m/s

Explanation:

A••••••••••••••••P••••B

Distance between A and B = S

Given that AP : PB = 4 : 1

So,

AP = 4S/5

PB = S/5

Use equation of motion: S = (v² - u²)/(2a)

From A to P

4S/5 = (V² - 1²)/(2a) ......(1)

From P to B

S/5 = (4² - V²)/(2a) .......(2)

Divide (1) by (2)

(4S/5) / (S/5) = [(V² - 1²)/(2a)] / [(4² - V²)/(2a)]

4 = (V² - 1)/(16 - V²)

4(16 - V²) = V² - 1

64 - 4V² = V² - 1

5V² = 65

V² = 65/5

V² = 13

V = √13 m/s


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