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A particle is executing SHM of period 4s. Then the time taken by it to move fromthe extreme position to half the amplitude is |
| Answer» R,● Answer-t = 0.67 s● Explanation-# Given-T = 4 sx = A/2# Solution-In SHM, displacement of particle starting from extreme position is given by eqn,x = ACOS(ωt)A/2 = Acos(ωt)cos(ωt) = 1/2Taking cos inverse,ωt = cosinv(1/2)2πt/T = π/3 t = T/6t = 4/6t = 0.67 sTherefore, time taken by particle to move from extreme position to half amplitude is 0.67 s.Hope this HELPS you... | |