1.

A particle has a velocity of 5.5m/s due east and a constant acceleration of 1m/s2 due east. The distance covered by it in the sixth second of motion is = ?

Answer» S6 = u + a/2(2n -1)S6 = 5.5 + 0.5(11)S6 = 11mExplanation:hope the ANSWER will HELP you


Discussion

No Comment Found

Related InterviewSolutions