1.

A particle falls from the top of a tower and it cover `(3)/(25)` of the total height from `t=2` sec to t=4 sec. The height of the tower is:-A. 200mB. 300mC. 500mD. 800m

Answer» `h_(1)=5(2)^(2)=20`
`h_(2)=5(4)=80`
`h_(2)-h_(1)=60=(3)/(25)H`
H=500m


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