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A particle falls from the top of a tower and it cover `(3)/(25)` of the total height from `t=2` sec to t=4 sec. The height of the tower is:-A. 200mB. 300mC. 500mD. 800m |
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Answer» `h_(1)=5(2)^(2)=20` `h_(2)=5(4)=80` `h_(2)-h_(1)=60=(3)/(25)H` H=500m |
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