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A particle experience an acceleration a = (4e–3t) m/s2 along positive x-axis, where t is time in s. If the initial velocity of the particle is 2 m/s along positive x-axis, the velocity of the particle when its acceleration becomes zero is 5 m/s2 10 m/s2 6 m/s2 |
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Answer» From the graph:a= 4−3t for t<4sGiven INITIAL VELOCITY u=12m/sWe know, dtdv =adv=adt∫ uv dv=∫ 04 4−3t dtv−12= 04 [ 8−3t 2 v−12=−3. 816 =−6v=12−6=6m/s In POSITIVE X direction.Explanation:Mark me as brainlist plzz follow me |
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