A particle executes SHM starting from its mean position, at t=0s. If it's velocity is √3bω, when it is at a distance b from the mean position, where ω=2πT. The time taken by the particle to move from b to the extreme position on the same side is

A particle executes SHM starting from its mean position, at t=0s. If i

1.	A particle executes SHM starting from its mean position, at t=0s. If it's velocity is √3bω, when it is at a distance b from the mean position, where ω=2πT. The time taken by the particle to move from b to the extreme position on the same side is
Answer» A particle executes SHM starting from its mean position, at $t = 0 s$ . If it's velocity is $\sqrt{3} b ω$ , when it is at a distance $b$ from the mean position, where $ω = \frac{2 π}{T}$ . The time taken by the particle to move from $b$ to the extreme position on the same side is

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A particle executes SHM starting from its mean position, at t=0s. If it's velocity is √3bω, when it is at a distance b from the mean position, where ω=2πT. The time taken by the particle to move from b to the extreme position on the same side is

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