A particle executes SHM represented by the equation , y= 0.02sin(3.14t+ (pi)/(2)) meter. Find maximum acceleration

A particle executes SHM represented by the equation , y= 0.02sin(3.14t

1.	A particle executes SHM represented by the equation , y= 0.02sin(3.14t+ (pi)/(2)) meter. Find maximum acceleration
Answer» SOLUTION :COMPARING equation `y= 0.02sin(3.14t+ (pi)/(2))`with the GENERAL from of the equation , `y= A sin(omegat+phi_(0))` Maximum ACCELERATION `a_("max")= -Aomega^(2)= -0.02 xx (3.14)^(2)= 0.1972 ms^(-2)`