A parallelogram has vertices P(u, 4),Q(7,11), R(a, 4) and S(1,-3). Fin

1.	A parallelogram has vertices P(u, 4),Q(7,11), R(a, 4) and S(1,-3). Find the valueof a.
Answer» As it is parallelogram the opposite sides are equal. hence the distance PQ = distance SR root (1-1)^2 + (-3-4)^2 = root (a-7)^2 + (4-11)^20 + (-7)^2 = a^2 - 14 a + 49 + (-7)^20 = a^2 - 7a - 7a +490= ( a-7) (a- 7)a= 7

A parallelogram has vertices P(u, 4),Q(7,11), R(a, 4) and S(1,-3). Find the valueof a.

Answer»

As it is parallelogram the opposite sides are equal.

hence the distance PQ = distance SR root (1-1)^2 + (-3-4)^2 = root (a-7)^2 + (4-11)^20 + (-7)^2 = a^2 - 14 a + 49 + (-7)^20 = a^2 - 7a - 7a +490= ( a-7) (a- 7)a= 7

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A parallelogram has vertices P(u, 4),Q(7,11), R(a, 4) and S(1,-3). Find the valueof a.

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