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A parallel sides glass slab of thickness 4cm is made of a material of refractive index sqrt3. When light is incident on one of the parallel faces at an angle of 60^@, it emerges from the other parallel face. Find the lateral displacement of the emergent beam. |
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Answer» Solution :By snell.s law `mu= (SIN i)/(sin r),SQRT3= (sin 60^@)/(sin r)` `sqrt3=sqrt3/(2 sin r), sin r=1/2`, Hence, `r=30^@`, Lateral shift `=t/ (COS r) sin (i-r)` `=4/(cos 30^@) sin (60^@-30^@)=4((sin 30^@)/(cos 30^@))=4 TAN 30^@=4/sqrt3`
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