1.

A parallel plate capacitor of acapacitance 100pF is to be constructed by using paper sheets of 1mm thicknessas dielectric. If the dielectricconstant of paper is 4, thenumber of circular metal foilsof diameter 2cm each requiredfor the purpose is,​

Answer»

The answer will be 10

Explanation:

According to the problem the capacitance of the parallel plate is 100 pF

The thickness of the SHEETS is given as 1 mm

The dielectric CONSTANT of the paper is given

Now let the number of foils required is p and it will need (p-1) capacitors

Now let the dielectric constant is K

Therefore the capacitance is given by

c = ke0(p-1)A/d

=> (p-1) = cd/ke0A = cd/k x 4πe0A = 4π/πr^2 =  4cd/ k x 4πe0r^2

                 = 4 x 10^(-1) x 1 x 10^(-3) x 9 x 10^9/4(1.0 x 10^(-2))^2 = 9

p = 10



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