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A parallel plate capacitor having plate area `0.5 m^(2)` and plate separation of 5 mm is complete filled with a dielectric of dielectric constant 10. What is the instantaneous displacement current, if it is being charged at the rate of `100 V//s`? `[epsilon_(0)=8.85 xx 10^(-12)C^(2)N//m^(2)]`A. `8.85 mu A`B. `0.885 mu A`C. `0.177 mu A`D. `1.77 mu A` |
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Answer» Correct Answer - B The capacity of the parallel plate capacitor is given by `C = (Kaepsilon_0)/d = (10 xx 5 xx 10^(-1) xx 8.85 xx 10^(-12))/(5 xx 10^(-3))` `=8.85 xx 10^(-9) F` `:.` Displacement current `I_(d) = C(dV)/(dt)` `=8.85 xx 10^(-9) xx 100` `=8.85 xx 10^(-7)A` `=0.885 xx 10^(-6) A` `:. I_(d) = 0.88r muA`. |
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