A parallel capacitor has plate of length l, width w and separation of plates is d. It is connected to a battery of emf V. A dielectric slab of the same thickness d and of dielectric constant K=4 is being inserted between the plates of the capacitor. At what length of the slab inside plates, will the energy in the capacitor be two times the initial energy stored?

A parallel capacitor has plate of length l, width w and separation of

1.	A parallel capacitor has plate of length l, width w and separation of plates is d. It is connected to a battery of emf V. A dielectric slab of the same thickness d and of dielectric constant K=4 is being inserted between the plates of the capacitor. At what length of the slab inside plates, will the energy in the capacitor be two times the initial energy stored?
Answer» A parallel capacitor has plate of length $l$ , width $w$ and separation of plates is $d$ . It is connected to a battery of emf $V$ . A dielectric slab of the same thickness $d$ and of dielectric constant $K = 4$ is being inserted between the plates of the capacitor. At what length of the slab inside plates, will the energy in the capacitor be two times the initial energy stored?

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