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a object is placed at a distance of 15cm from a concave mirror of focal length 6 cm.if the height of the object is 4 cm.find the distance,nature and size of the image |
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Answer» Explanation: Focal LENGTH (f)=10cm Object distance (u)=15cm. Height of the object=6cm. Using the mirror's formula, 1/f=1/v+1/u 1/-10=1/v+1/-15 1/v=1/-10+1/15 1/v=(-3+2)/30 v=-30cm Since, IMAGE distance is negative, therefore,it is real and inverted. Now, magnitude=-v/u =-(-30)/15 =2 Since, magnitude in greater than 1, therefore image is MAGNIFIED Also,m=H of image/H of object. 2=H of image/6 Height of image =12cm. characteristics of image are Real, inverted and Magnified. |
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