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A object is placed at 25 focal length 60 what image concave distance? |
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Answer» 1/f=1/u+1/vu=-25cm1/-15=1/-25+1/(+v)===>1/v=-1/15+1/251/v=-25+15/15*251/v=-2/75v=-75/2m=-(v/u)=-(75/2/-25/1)=-3/2=-1.5m=-1.5so Image is magnified and real ,invertedORho = 4 cmu = - 25 cmf = - 15 cm1/u + 1/v = 1/f-1/25 + 1/v = -1/151/v = -1/15 + 1/251/v = (-5 + 3) / 751/v = -2/75v = -75/2 = - 37.5 CMHI / HO = -v/uhi / 4 = 75/2 * (-25)hi = -3/2 * 4hi = -3 * 2 = -6 cmTherefore the image is real inverted . It is FORMED 6cm away from the mirror in FRONT of the mirror.Was this answer helpful.....plz mark as brainiest..... follow me... |
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