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A O 24 g sample of compound of oxygen and boron was foundby analysis to contain 0:096 g of boron and 0.144 g of oxygen.Calculate the percentage composition of the compound byweight. |
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Answer» Mass of compound = 0.24 g and, mass of boron = 0.096 g Percentage of boron in the compound = mass of boron / mass of compound * 100 = 0.096/0.24 * 100 = 40% Mass of oxygen = 0.144 g again, mass of compound = 0.24 g Percentage of oxygen in compound = mass of oxygen/mass of of compound * 100 = 0.144/0.24 * 100 = 60% Thus, the percentage of oxygen and boron in the compound is 60% and 40% respectively. Thank you friend |
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