A number plus two-thirds of itself, plus one halfof itself plus one-se – InterviewSolution

1.

A number plus two-thirds of itself, plus one halfof itself plus one-seventh of itself equals 97. Findthe number.

Answer»

Let the number be xx+(2/3)x+(1/2)x+(1/7)x=97

lcm of (1,3,2,7)=42

=>(42x/42)+(28x/42)+(21x/42)+(6x+42)=97=>(42x+28x+21x+6x)/42=97=>97x/42=97=>97x=97×42=>x=(97/97)×42=>x=1×42=>x=42

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