A number N when increased by 30% becomes 520. Find the value of N.

1.	A number N when increased by 30% becomes 520. Find the value of N.
Answer» GIVEN:- A number N when INCREASED by 30% becomes 520. To FIND:- Value of N. Solution:- According to the question, $➾\:N + 30 \:\%= 390$ $➾\:N + \dfrac{30N}{100} = 390$ $➾\:N + \dfrac{3N}{10} = 390$ $➾\:\dfrac{10N+3N}{10} = 390$ $➾\:\dfrac{13N}{10} = 390$ $➾\:N = \dfrac{390×10}{13}$ ${\boxed{➾\:N=30}}$ Hence, the value of N is 30. ━━━━━━━━━━━━━━━━━━

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