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A number is selected from numbers 1 to 25. The probability that it is prime isA \(\frac{2}3\)B \(\frac{1}6\)C \(\frac{1}3\)D \(\frac{9}{25}\) |
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Answer» Total numbers of elementary events are: 25 Let E be the event of getting a prime number Favorable outcomes are: 2, 3, 5, 7, 11, 13, 17, 19, 23 Numbers of favorable outcomes are = 9 P (prime number) = P (E) = \(\frac{9}{25}\) |
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