1.

A number is selected from numbers 1 to 25. The probability that it is prime isA  \(\frac{2}3\)B  \(\frac{1}6\)C  \(\frac{1}3\)D  \(\frac{9}{25}\)

Answer»

Total numbers of elementary events are: 25 

Let E be the event of getting a prime number 

Favorable outcomes are: 2, 3, 5, 7, 11, 13, 17, 19, 23 

Numbers of favorable outcomes are = 9 

P (prime number) = P (E) = \(\frac{9}{25}\)



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