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A number consists of two digits whose sum is 9 if the digits are reversed the new number is 3/8 of first number. find the number |
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Answer» LET the one's digit no. =X so, tens digit no. =9-x No formed: x+10(9-x) x+ 90 -10x 90-9x After interchanging Ones digit = 9-x tens digit =x New no formed: 9-x+ 10(x) 9-x+10x 9-9x ATQ 3/8(90-9x) = 9-9x 135/4-27x/8=9-9x 9x -27x/8=9-135/4 The question is wrong the answer will be in NEGATIVE. |
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