1.

A number consists of two digits whose sum is 9 . if 27 is subtracted from the number its digits are reverse d .find the number

Answer» LET the ones DIGIT be x and the tens digit be y.
Then, Number= (10y + x)
A/q
x + y = 9................(i)

And, 10y + x - 27 = 10x + y
=> 10y - y + x - 10x = 27
=> 9Y - 9x = 27
=> 9 ( y - x ) = 27
=> y - x = 3...............(II)

Now, By ADDING eq. (i) and (ii), we get
x + y = 9
- x + y = 3
----------------
2y = 12
( y = 6 )
Now, put the value of y = 6 in eq. (i)
x + y = 9
x + 6 = 9
x = 9 - 6
( x = 3 )
Then, Number = 10y + x
= 10 ( 6 ) + 3
= 60 + 3
= 63.............Answer.
Hence, The required number is 63.


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