A number consists of two-digits of which tens digit exceeds the units

1.	A number consists of two-digits of which tens digit exceeds the units digit by 3. The number is 7 timesthe sum of its digits, find the number.
Answer» Answer: 63 Step-by-step EXPLANATION: Assume Number = XY [ XY Can be rewritten as X10+Y For Example : 53 can be written as (510)+3 = 53 ] Given X=Y+3, so X-Y=3 -----(1) Also Given , (X*10)+Y = 7(X+Y) Simplify and we get, 3X-6Y=0 -----(2) solve (1)&(2) X=6 Y=3 Number = 63

A number consists of two-digits of which tens digit exceeds the units digit by 3. The number is 7 timesthe sum of its digits, find the number.

Answer»

Answer:

Step-by-step EXPLANATION:

Assume Number = XY

[ XY Can be rewritten as X*10+Y

For Example : 53 can be written as (5*10)+3 = 53 ]

Given X=Y+3, so X-Y=3 -----(1)

Also Given , (X*10)+Y = 7(X+Y)

Simplify and we get, 3X-6Y=0 -----(2)

solve (1)&(2)

X=6

Y=3

Number = 63