A normal at any point (x,y) to the curve y=f(x) cuts a triangle of unit area with the co-ordinate axes, then the differential equation of the curve is:

A normal at any point (x,y) to the curve y=f(x) cuts a triangle of uni

1.	A normal at any point (x,y) to the curve y=f(x) cuts a triangle of unit area with the co-ordinate axes, then the differential equation of the curve is:
Answer» A normal at any point $(x, y)$ to the curve $y = f (x)$ cuts a triangle of unit area with the co-ordinate axes, then the differential equation of the curve is: