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A non-viscous liquid of constant density `500 kg//m^(3)` flows in a variable cross-sectional tube. The area of cross section of the tube at two points `P` and `Q` at heights of `3 m` and `6 m` are `2 xx 10^(-3) m^(3)` and `4 xx 10^(-3) m^(3)`, respectively. Find the work done per unit volume by the forces of gravity as the fluid flows from point `P` to `Q`. |
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Answer» Work done by per unit volume by force of gravity `=-` change in potential energy per unit volume `:. W=/_U=-rhog(h_(2)-h_(1))=-rhot(6-3)` `=-3xx500xx10=-15xx10^(4)J//m^(3)` |
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