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A non-conducting ring of radius r has charge q distributed unevenly over it. What will be the equivalent current if it rotates with an angular velocity `Omega`? |
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Answer» In one rotation, charge q crosses any fixed point near the ring. Time period of rotation `T=2 pi//omega` `:.` Current = charge crossing per second `q/T = q/( 2pi // omega) =q omega/2pi` |
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