1.

A NO CONSIIST OF 2 DIGITS THE SUM OF THE DIGIT IS 11 ON REVERSING THE DIGITS THE TOTAL BECOMES LESS BY 63. THE NUMBER IS ?

Answer»

Let's take the number be 10x+y where x is the digit in tens place and y is in ONES place.So sum of DIGITS =11=x+y. on reversing the number becomes 10y+x.
it is given upon reversing total is less than 63.this means 10y+x-10x-y=63. upon simplification it becomes y-x=7.solving both EQUATIONS gives y=9andx=2. The ORIGINAL number is 29.



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